tugas1

Dwi mulyadi
2012420080

public class PerbaikanArray {

/**

* @param args the command line arguments

*/

public static void main(String[] args) {

// TODO code application logic here

//

String [] perhitungan= {"a","b","c","d","e","f","g","h","i","j"

,"k","l","m","n","o","p","q","r","s","t"

,"u","v","w","x","y","z"," "};

String []hasil= {"G","K","M","W","Q","Y","X","Z","N","O","P",

"A","R","U","T","V","Z","H","J","L","B","C",

"D","E","F","I","7","5","3","2","6","8","9",

"4"};

String hasil = JOptionPane.showInputDialog(null, "Masukkan hasil anda").toUpperCase();

char a[] = kode.toCharArray(); // mengkonversi string ke char

for (int i = 0; i < a.length; i++) { // inputan

for (int j = 0; j < hasil.length; j++) { //output.an

if(String.valueOf(a[i]).equalsIgnoreCase(sandi[j]))

System.out.print(""+perhitungan[j]);

}

}

}

}

Perhitungan eksekusi =

perhitungan [] dieksekusi 1 kali

hasil [] dieksekusi 1 kali

i=0 dieksekusi 1 kali

i<a.lenght dieksekusi n kali

i++ dieksekusi n kali

j=0 dieksekusi 1 kali

j<hasil.lenght dieksekusi m kali

j++ dieksekusi m kali

ir dieksekusi 1+m kali

---

5+2n+3m => jadi 2n+107

Jumlah = m=34

5+2n+3.34

5+2n+102

2a+107

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Posted by arek informatika, Published at 14.24 and have 0 komentar