Tugas 1 Henry 2012420114

public class PerbaikanArray {

    /**

     * @param args the command line arguments

     */

    public static void main(String[] args) {

        // TODO code application logic here

//       

   

       String [] perhitungan= {"a","b","c","d","e","f","g","h","i","j"

                              ,"k","l","m","n","o","p","q","r","s","t"

                              ,"u","v","w","x","y","z"," "};

        String []hasil=      {"G","K","M","W","Q","Y","X","Z","N","O","P",

                               "A","R","U","T","V","Z","H","J","L","B","C",

                               "D","E","F","I","7","5","3","2","6","8","9",

                               "4"};

String hasil = JOptionPane.showInputDialog(null, "Masukkan hasil anda").toUpperCase();

      char a[] = kode.toCharArray(); // mengkonversi string ke char

      for (int i = 0; i < a.length; i++) { // inputan

          for (int j = 0; j < hasil.length; j++) { //output.an

            if(String.valueOf(a[i]).equalsIgnoreCase(sandi[j]))

                  System.out.print(""+perhitungan[j]);

    }

}

    }

        }

Perhitungan eksekusi =

perhitungan []                            dieksekusi        1          kali

hasil []                                      dieksekusi        1          kali

i=0                                            dieksekusi        1          kali

i<a.lenght                                  dieksekusi        n          kali

i++                                           dieksekusi        n          kali

j=0                                            dieksekusi        1          kali

j<hasil.lenght                             dieksekusi        m         kali

j++                                           dieksekusi        m         kali

ir                                              dieksekusi        1+m      kali

---

                                                            5+2n+3m => jadi 2n+107                                                       

Jumlah = m=34

               5+2n+3.34

               5+2n+102

                2a+107

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Posted by arek informatika, Published at 01.50 and have 0 komentar