Tugas 1 : Menghitung Running time

 Menghitung Running time - by Rian Dhewantara. Berikut ini adalah tugas 1 mengenai cara  untuk menghitung running time sebuah program. Langsung saja saya contohkan dengan codingan di bawah ini.


package rahasia;

import javax.swing.JOptionPane;

/**
 *
 * @author Dhewan
 */
public class Rahasia {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
       String [] aa = {"a","b","c","d","e","f","g","h","i","j","k","l","m","n",
                       "o","p","q","r","s","t","u","v","w","x","y","z"," "};
       String [] bb = {"10","20","30","40","50","60","70","80","90","00","11",
                       "21","31","41","51","61","71","81","91","01","12","22",
                       "32","42","52","62","72"};
      
      
      
         String kode =JOptionPane.showInputDialog(null,"masukkan sandi anda");
        char[] c = kode.toCharArray();
        for (int i=0;i<c.length;i++){
            for (int j=0;j<aa.length;j++){
                if (String.valueOf(c[i]).equalsIgnoreCase(aa[j]))
                    //equels
                    System.out.print(bb[j]);
            }
        }
        System.out.println("");
    }
}


RUNNING TIME
String [] aa // sesuai dg jumla array                                                                             27 x
String [] bb // sesuai dg jumla array                                                                             27 x
String kode = JOptionPane.showInputDialog(null, "Masukkan sandi anda");                n x
int i = 0;                                                                                                                     1 x
i < c.length;                                                                                                                 n x
i++                                                                                                                             n x
int j = 0;                                                                                                                     1 x
j < aa.length;                                                                                                               n x n
j++                                                                                                                             n x n
if(String.valueOf(c[i]).equalsIgnoreCase(aa[j]))                                                            n x n +               


56  + 3n + 3n2 kali = T(n) = O ( n3 )

Nama : Mochammad Rian Dhewantara

Nim : 2012420093

Fakultas : Teknik Informatika

UNITOMO

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Posted by arek informatika, Published at 21.28 and have 0 komentar